A player throws a ball upwards with an initial speed of 29.4 ms -1 . The height to which the ball rises and the time taken to reach the player's hands are
Text Solution
Verified by ExpertsThe correct answer is:
B
From u = 
h = 
= 44.1 m
h' = ut + 1/2 gt 2 = 29.4 t – 1/2 (9.8)t 2 = 0
∴ ∴ t = 6 s
Using g = u/t, where t is time taken to reach the highest point, we get
t = u/g = 29.4/9.8 = 3 s
By symmetry, the time taken by the ball to reach from the highest point to the hands of the player is 3s.
∴ ∴ total time = 3 + 3 = 6s.
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